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Riddle 3

January 14, 2011 Leave a comment Go to comments

Seems that the Riddle 1 and Riddle 2 are so easy, right?

Well, here is another Riddle which is maybe a little more difficult than the previous Riddles.

Are you ready?

Here we go . . .

There are given 8 stones which all of them are similar in size and shape.

The case is:

There is one of the stones that has a different mass from the rest. It is the heaviest stone from the other. How do you find out that heaviest stone, if you are allowed to use the Pair of Scales only for TWO times?

Good Luck 🙂

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Categories: Riddles
  1. Winny
    January 14, 2011 at 9:33 am

    when we lifted the stone to put on the scale, we automatically know which one is the heaviest even without using the scale.

    • January 14, 2011 at 10:28 am

      Good answer, but still wrong.
      How if the different mass is very small so it is very hard to be recognize which one is the heaviest? 🙂
      Try to solve it again, Winny.
      I know you can do it.
      Good Luck…

  2. January 14, 2011 at 10:21 am

    use ur hand..

  3. kuman
    January 14, 2011 at 10:22 am

    use ur hand

    • January 14, 2011 at 3:31 pm

      Good answer, but still wrong.
      How if the different mass is very small so it is very hard to be recognize which one is the heaviest? 🙂
      Try to solve it again, Winny.
      I know you can do it.
      Good Luck…

  4. albert_hrs
    January 14, 2011 at 3:41 pm

    First divided into 2-3-3
    then divided into 1-1 or 1-1-1

    is that count as two times?

    • January 14, 2011 at 4:17 pm

      Don’t really got what does it means…
      Can you please make it more clear? 🙂
      Anyway, Thank you…

  5. Steven
    January 14, 2011 at 4:40 pm

    put 3 stones in left hand n 3 in right hand.. places them in the scale. there are 3 situations which will be happened…
    1. if the right ones is heavier than take the stones… so it will be only 3 of them.. take 1 n place it in the right scale.. place 1 too in the left scale.. if the right is heavier, that means the right one is the answer… if the left is heavier, than the left one is the answer.. if the scale in a balance position… so the only stone which isn’t placed in the scale is the answer…
    2. if the left ones is heavier… repeat the first way n you will know the answer..
    3. if the scale in a balance position….. you know what that means right??? it means there are only two of them.. n the stones isn’t in the scale. they are in your hand.. so.. just place 1 in the right n 1 in the left.. n you know the answer..
    how is it?? wkwkwk.. XD

  6. kuman
    January 14, 2011 at 5:30 pm

    first divide it into 2 (4-4)
    and scale it..
    then divide it again into 2..
    after that put the stones on the scale one by one on each side..
    then u’ll know which one is the heaviest..
    haha..

    NB: “first….then” is only written down so that the scale is used twice.

    • January 15, 2011 at 3:59 am

      put the stones on the scale on by one?
      isn’t that means you will used the scale more than two times…?

  7. Melisa Yang
    January 15, 2011 at 1:10 pm

    First, we put three stones in each of the scales .. if heavy rocks on both scales are equal, we take a stone in each of the scales and exchange with 2 other stones that have not been weighed. of course we will know where the heavier weights and also a stone which is more severe than others.. =)

  8. sususapii
    January 15, 2011 at 1:31 pm

    there is 8 stones, rite?
    divide it into 3 (3-3-2)

    *FIRST, put 3 stones to every side of the scales (put aside 2 stones for a while) and see which side is heavier..

    *SECOND, take 3 stones from the side you hev scaled just now, which u think is heavier & divide it into 3 (1-1-1)

    *THIRD, take 2 from 3 of the stones & put 1 to each side of the scale..now let the scale works & see which stone is heavier!
    if 2 of the stones u took on the 3rd step weight the same, then the heaviest stone must be the one u dont put on the scale!

    If both side weight the same at the FIRST step, take the 2 stones u put aside on aech side of the scales & u’ll hev d answer!

    SEE? It’s easy :p

    • January 19, 2011 at 1:31 pm

      Yeah, Absolutely very easy…
      Good job!

  9. RippiR
    January 18, 2011 at 5:03 am

    easy one.
    bagi dulu jadi 3 grup, dengan isi 3,3,2. timbang 2 grup pertama, jika seimbang, brrt tinggal di grup ke3 yg lbh berat, timbang antara keduanya. dapat deh dgn 2x timbang..

    contohnya: kita ksh nama 1-8. yg lbh berat itu misalkan no 8.
    pertama timbang dulu 1,2,3 dengan 4,5,6. mereka seimbang, brrt antara 7 dan 8. timbang az 7 dan 8, dpt d yg lbh berat tu 8. (2x timbang)

    Lalu misalnya yg berat tu di 5.
    sama juga, pertama timbang dulu 1,2,3 dan 4,5,6. tentunya 4,5,6 lbh berat, jadi acuhkan az 7 dan 8.
    kemudian ambil dua batu dari 4,5,6 dan timbang.
    klo ambil 4 dan 5 atau 5 dan 6 kan lngsg nmpk 5 lbh berat, tapi klo yg keambil 4 dan 6, dan tentunya mrk seimbang, dpt juga d 5 yg lbh berat. (2x timbangan).

    nah! time for payback.
    Try to solve this. 🙂
    a little challenge

    Detektif Jack dimintai tolong seorang tuan tanah kaya untuk menyelidiki kasus pencurian uang.
    Tuan tanah itu bernama Prince D

    Prince D berkata “Uang itu ada dalam sebuah amplop, tapi sekarang amplop itu isinya kosong. Pasti ada yang mencurinya!!”
    Detektif mencurigai ini pasti perbuatan orang dalam. Lalu menanyai penghuni rumah mewah itu satu persatu.

    Pertama adalah si sopir, Roy.
    “Saya memang yg pertama membawa amplop itu, dan saya tahu itu isinya uang namun amplop itu langsung saya taruh di atas meja di ruangan pribadinya tuan Prince” kata Roy.

    Kedua si tukang bersih2, Faritz.
    “Saya memang melihat amplop diatas meja, saya tidak tahu isinya tapi saya merasa amplop itu sangat penting. Karena itu saya lalu menyelipkannya di sebuah buku antara halaman 185 & 186” ujar Faritz.

    Ketiga si nyonya tuan rumah, Ukhti Cool
    “Hawa rumah sangat dingin, karena itu saya ingin menyalakan pemanas di ruang pribadi suami saya. Tapi saya melihat amplop itu sudah jatuh di bawah meja. Saya penasaran, karena itu saya buka, tapi ternyata isinya kosong” celotehnya.

    Detektif Jack benar2 bingung… semua tersangka memiliki alibi, tapi semua tersangka juga ada kemungkinan mencuri.
    Bisa saja Roy sudah mencuri sebelum menaruh di meja. Atau mungkin Faritz sebelum diselipkan di buku. Atau si nyonya pura2 membuka dan mengatakan bahwa amplopnya sudah kosong. Atau juga tidak menutup kemungkinan si Prince mengaku pura2 kecurian untuk mendapatkan tanggungan asuransi, padahal sebenarnya pelakunya justru dia sendiri??

  10. Mr.X
    January 18, 2011 at 9:11 am

    Easy..
    just divided 6 and 2
    then scale 3-3
    if the heaviest stone doesn’t exist between 6 stones
    just scale 2 stones left.
    but if the heaviest stone exist between 6 stones
    It means just 3 left.. take one out of the scale and compare 1-1

    • January 19, 2011 at 1:32 pm

      Good job, Mr.X …

  11. Unknown
    January 18, 2011 at 6:37 pm

    pertama timbang 3 – 3
    kalau seimbang, berarti 1 dari 2 batu yang belum ditimbang yang lebih berat, yang tinggal ditimbang dengan cara 1 – 1.
    kalau tidak seimbang, ambil 3 batu yang ditimbang lebih berat, lalu ambil 2 dari 3 untuk ditimbang. Jika seimbang, berarti yang 1 lagi lebih berat. Jika tidak seimbang, yang lebih berat ya itulah batunya.

    • January 19, 2011 at 1:32 pm

      Yes, that is the answer…
      Good job…

  12. RippiR
    January 23, 2011 at 12:33 am

    Sooo… nobody can answer my Riddle yeah?
    ckckckkckc

    • January 25, 2011 at 10:35 pm

      Psikita had tried to answer it by sending the answer to your e-mail address …
      Have you checked it yet? 🙂
      Thanks

  13. kuman
    January 23, 2011 at 10:38 pm

    @rippir
    amplop asliny ada di buku antara hal 185&186

  14. RippiR
    January 29, 2011 at 8:26 am

    @kuman: Sorry, wrong.. Try again.

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